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25^(3a+5)=1/125
We move all terms to the left:
25^(3a+5)-(1/125)=0
We add all the numbers together, and all the variables
25^(3a+5)-(+1/125)=0
We get rid of parentheses
25^(3a+5)-1/125=0
We multiply all the terms by the denominator
(25^(3a+5))*125-1=0
We move all terms containing a to the left, all other terms to the right
(25^(3a+5))*125=1
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